Use the law of conservation of energy to determine the final speed of the box if it starts from rest.?

A gardener exerts a force of 1.5E2 N [22 derees below the horizontal] in pushing a large 18 kg box of flower seeds a distance of 1.6 m. The coefficient of kinetic friction between the box and the floor is 0.55.

Use the law of conservation of energy to determine the final speed of the box if it starts from rest.?
Positive Work = F dot distance

Negative Work (friction) = MG * mu dot distance



Work = 1500 N cos 22 *1.6 M - 18 Kg * 9.8066 m/S^2*.55 * 1.6M



KE = .5 * Mass * V^2: KE = net Work

solving for Velocity = 15.1654 m/s

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